Training Guide > Radiation Tutorials > Thermal Insulator Tutorial > Setting Boundary Conditions and Values
Setting Boundary Conditions and Values
The thermal insulator consists of a closed heated box with two internal solid glass panels surrounded by air. The boundary specifications required for this analysis are wall thermal conditions and radiation properties at the boundaries.
A fixed heat flux of 1000 W/m^2 needs to be applied to the base of the box to provide the heat source. The top of the box is given a fixed temperature of 300 K which corresponds to the temperature of the environment. The vertical sides of the solid panels which are in contact with the environment need to be set to a fixed heat flux of -62.5 W/m^2. All other wall boundary conditions will be considered to be adiabatic, which is the default condition. Contact-type conducting boundaries will also be used at solid-fluid interfaces.
Optical radiation properties emissivity, reflectivity, transmissivity, and radiation temperature must also be set at all boundaries. Kirchoff's Law (emissivity = absorptivity) is assumed by the solver and you should also check that, for each boundary or interface, emissivity + reflectivity + transmissivity = 1.
We will start with the wall boundary definitions for the fluid region.
- Select the Regions > Fluid > Boundaries > collector > Physics Conditions > Thermal Specification node.

- Set the Method property to .

The heat flux value for this boundary can now be set.
- Within the same collector node, select the Physics Values > Heat Flux > Constant node.

- Set the Value property to
1000 W/m^2.

STAR-CCM+ adds the decimal point and units automatically, so by simply entering 1000 you get an entry of 1000.0 W/m^2. A positive value for heat flux indicates that heat is entering the domain while a negative value would indicate that heat is leaving the domain.
- Within the same Physics Values node, select the Surface Emissivity > Constant node and set the Value property to
1.
- Within the same Physics Values node, select the Surface Reflectivity > Constant node and set the Value property to
0.
- Within the same Physics Values node, select the Surface Transmissivity > Constant node and check that the Value property is set to
0.
The conditions for the side-1, side-2 and side-3 wall boundaries (side walls of the fluid region) will be left at the default adiabatic setting but the optical properties at these boundaries must be set. We will set the side-1 wall boundary next.
- Select the Regions > Fluid > Boundaries > side-1 > Physics Values > Surface Emissivity > Constant node.

- Set the Value property to
0.95.
- Within the same Physics Values node, select the Surface Reflectivity > Constant node and set the Value property to
0.05.
- Within the same Physics Values node, select the Surface Transmissivity > Constant node and check that the Value property is set to
0.
The conditions for the side-2 and side-3 wall boundaries are identical to those for the side-1 boundary and may be set up in the same way manually or copied and pasted from the side-1 boundary.
- Right-click the Regions > Fluid > Boundaries > side-1 node and select .

- Right-click the Regions > Fluid > Boundaries > side-2 node and select

- Right-click the Regions > Fluid > Boundaries > side-3 node and select Check that the radiative boundary conditions are correct.
The conditions for the top wall boundary are set next.
- Select the Regions > Fluid > Boundaries > top > Physics Conditions > Thermal Specification node.

- Set the Method property to .
- Within the same top node, select the Physics Values > Static Temperature > Constant node.
- Check that the Value property is set to
300 K.
- Within the same Physics Values node, select the Surface Emissivity > Constant node and check that the Value property is set to
0.8.
- Within the same Physics Values node, select the Surface Reflectivity > Constant node and set the Value property to
0.05.
- Within the same Physics Values node, select the Surface Transmissivity > Constant node and set the Value property to
0.15.
Now the boundary conditions must be set for the solid-fluid interfaces. The emissivity and reflectivity of the solid-fluid interfaces must be specified at each Interface [In-place #] boundary, not the Interface boundary, as the latter became defunct when the interface was created (see the previous section Creating Interfaces). However, transmissivities for interface boundaries are set under the Interfaces node rather than at the boundaries within the Regions node.
- Open the bottom-solid1 [In-place 2] node and, following the instructions given above for the wall boundaries, set the emissivity and reflectivity of the interface to
0.775 and 0.075, respectively.

- Similarly, open the bottom-solid2 [In-place 4] node and set the emissivity and reflectivity of the interface to
0.725 and 0.1, respectively.
- Open the top-solid1 [In-place 1] node and set the emissivity and reflectivity of the interface to
0.8 and 0.05, respectively.
- Open the top-solid2 [In-place 3] node and set the emissivity and reflectivity of the interface to
0.75 and 0.075, respectively.
Note that it is not necessary to set the emissivity and reflectivity for interface boundaries in the solid region. We can now set the solid wall boundary conditions and values in a similar way to the fluid ones.
- Select the Regions > Solid > Boundaries > side-solid1 > Physics Conditions > Thermal Specification node.
- Set the Method property to
The heat flux value for this boundary can now be set.
- Within the same side-solid1 node, select the Values > Heat Flux > Constant node.

- Set the Value property to
-62.5 W/m^2. The negative value indicates that heat is leaving the domain.

- Within the same Physics Values node, select the Surface Emissivity > Constant node and set the Value property to
0.
- Within the same Physics Values node, select the Surface Reflectivity > Constant node and set the Value property to
1.
- Within the same Physics Values node, select the Surface Transmissivity > Constant node and check that the Value property is set to
0.
The conditions for wall boundary side-solid2 are the same as for side-solid1 and may be copied and pasted from the side-solid1 boundary.
- Right-click the Regions > Solid > Boundaries > side-solid1 node.
- Select from the pop-up menu.
- Right-click the Regions > Solid > Boundaries > side-solid2 node.
- Select from the pop-up menu.
Finally, we must now specify the transmissivities of the interface boundaries:
- Select the Interfaces > In-place 1 > Physics Values > Surface Transmissivity node.

- Change the Optical Transmissivity property value to
0.15.
- Select the Interfaces > In-place 2 > Physics Values > Surface Transmissivity node.
- Change the Optical Transmissivity property value to
0.15.
- Select the Interfaces > In-place 3 > Physics Values > Surface Transmissivity node.
- Change the Optical Transmissivity property value to
0.175.
- Select the Interfaces > In-place 4 > Physics Values > Surface Transmissivity node.
- Change the Optical Transmissivity property value to
0.175.
Note that the transmissivity values of the interfaces In-place 1 and In-place 2 (and similarly of In-place 3 and In-place 4) were set equal since they belong to the same glass plate. This is because transmissivity is physically a volumetric property in contrast to emissivity and reflectivity which are surface properties.
- Save the simulation.
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