Introduced
3.0
Description
Sets the position of an FxOperator in the FxTree.
Scripting Syntax
SetFxOpPos( [FxOp], [x], [y] )
Parameters
|
Parameter |
Type |
Description |
|
FxOp |
String or FxOperator |
Object pointer or Object name of FxOperator to connect. Default Value: Current selection. Note: If the current selection is not a valid FxOperator, an error occurs. |
|
x |
Specifies the position of the FxOperator in X. Default Value: 0 |
|
|
y |
Specifies the position of the FxOperator in Y. Default Value: 0 |
Examples
VBScript Example
' This example creates an FxTree, adds the FileInput operator
' to it, sets its position in X and Y, and prints the new positions.
set oTree = CreateFxTree()
set oFxOp = AddFxOp( oTree, "File Input" )
' Print the positions before updating
printPositions( oFxOp )
' Move the operator icon upwards and to the left
SetFxOpPos oFxOp, 143, 88
' Print the positions after updating
printPositions( oFxOp )
function printPositions( in_operator )
' There is no scripting command to get the positions
' of an FxOperator, but you can use the object model:
Application.LogMessage "X and Y positions of the " _
& oFxOp.Name & " operator: " _
& oFxOp.PositionX & ", " _
& oFxOp.PositionY
end function
' Output of above script:
'INFO : "X and Y positions of the FileInput operator: 215, 146"
'INFO : "X and Y positions of the FileInput operator: 143, 88"
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