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EvaluatePosition (NurbsCurve) *

Description

Returns a 3D vector containing the position, tangent in U direction, normal and bi-normal at a given U value.

Scripting Syntax

NurbsCurve.EvaluatePosition( UValue )

C# Syntax

Object NurbsCurve.EvaluatePosition( Double in_dUValue );

Parameters

Return Value

A 1-dimensional Array containing the position, tangent, normal and bi-normal.

Examples

1. VBScript Example

set oRoot = Application.ActiveProject.ActiveScene.Root
set oArc = oRoot.AddGeometry( "Arc", "NurbsCurve" )
aValues = oArc.ActivePrimitive.Geometry.Curves(0).EvaluatePosition( 3.0 )

set oPosition = aValues(0)
logmessage "The position at 3.0 is x :" &  oPosition.x & " y: " _
   & oPosition.y & " z: " & oPosition.z

set oUTangent = aValues(1)
logmessage "The tangent in U at 3.0 is x :" & oUTangent.x & " y: " _
   & oUTangent.y & " z: " & oUTangent.z

set oNormal = aValues(2)
logmessage "The normal at 3.0 is x :" & oNormal.x & " y: " & oNormal.y _
   & " z: " & oNormal.z

set oBiNormal = aValues(3)
logmessage "The bi-normal at 3.0 is x :" & oBiNormal.x & " y: " _
   & oBiNormal.y & " z: " & oBiNormal.z

' Expected result:
'INFO : The position at 3.0 is x :1.16113870901785 y: 3.82776134292884 z: 0
'INFO : The tangent in U at 3.0 is x :0.956940009306386 y: -0.290285753334009 z: 0
'INFO : The normal at 3.0 is x :-0.290285753334009 y: -0.956940009306387 z: 0
'INFO : The bi-normal at 3.0 is x :0 y: 0 z: -1

2. JScript Example

/*
   See also the JScript example for NurbsCurveList.GetClosestCurvePosition2 which demonstrates
   how to use NurbsCurveList.GetClosestCurvePosition2 and NurbsCurve.EvaluatePosition as an
   (object model) alternative to the EvaluateCurveAt command.
*/

See Also

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