Delete



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Syntax

SapObject.SapModel.PatternDef.Delete

VB6 Procedure

Function Delete(ByVal Name As String) As Long

Parameters

Name

The name of an existing joint pattern.

Remarks

The function deletes the specified joint pattern. At least one joint pattern must be defined. The function will return an error if an attempt is made to delete the last joint pattern.

The function returns zero if the joint pattern is successfully deleted, otherwise it returns a nonzero value.

VBA Example

Sub DeletePattern()
   'dimension variables
      
Dim SapObject As Sap2000.SapObject
      Dim SapModel As cSapModel
      Dim ret as Long

   'create Sap2000 object
      Set SapObject = New SAP2000.SapObject

   'start Sap2000 application
      SapObject.ApplicationStart

   'create SapModel object
      Set SapModel = SapObject.SapModel

   'initialize model
      ret = SapModel.InitializeNewModel

   'create model from template
      ret = SapModel.File.New2DFrame(PortalFrame, 3, 124, 3, 200)

   'add joint pattern
      ret = SapModel.PatternDef.SetPattern("MyPattern")

   'delete joint pattern
      ret = SapModel.PatternDef.Delete("MyPattern")

   'close Sap2000
      SapObject.ApplicationExit False
      Set SapModel = Nothing
      Set SapObject = Nothing
End Sub

Release Notes

Initial release in version 11.00.

See Also

SetPattern

Return to SAP2000 Index


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