SetLocal

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Syntax

SapObject.SapModel.ConstraintDef.SetLocal

VB6 Procedure

Function SetLocal(ByVal Name As String, ByRef Value() As Boolean) As Long

Parameters

Name

The name of an existing constraint.

Value

Value is an array of six booleans that indicate which joint degrees of freedom are included in the constraint. In order, the degrees of freedom addressed in the array are U1, U2, U3, R1, R2 and R3.

Remarks

This function defines a Local constraint. If the specified name is not used for a constraint, a new constraint is defined using the specified name. If the specified name is already used for another Local constraint, the definition of that constraint is modified. If the specified name is already used for some constraint that is not a Local constraint, an error is returned.

The function returns zero if the constraint data is successfully added or modified, otherwise it returns a nonzero value.

VBA Example

Sub SetLocalConstraint()
   'dimension variables
      Dim SapObject As Sap2000.SapObject
      Dim SapModel As cSapModel
      Dim i as long
      Dim ret As Long
      Dim Value() As Boolean

   'create Sap2000 object
      Set SapObject = New SAP2000.SapObject

   'start Sap2000 application
      SapObject.ApplicationStart

   'create SapModel object
      Set SapModel = SapObject.SapModel

   'initialize model
      ret = SapModel.InitializeNewModel

   'create model from template
      ret = SapModel.File.New2DFrame(PortalFrame, 3, 124, 3, 200)

   'define new constraint
      redim Value(5)
      for i = 0 To 5
         Value(i) = True
      Next i
      ret = SapModel.ConstraintDef.SetLocal("Local1", Value)

   'close Sap2000
      SapObject.ApplicationExit False
      Set SapModel = Nothing
      Set SapObject = Nothing
End Sub

Release Notes

Initial release in version 11.00.